-2[x-3(x-1)-5]=2(x+2)

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Solution for -2[x-3(x-1)-5]=2(x+2) equation:


Simplifying
-2[x + -3(x + -1) + -5] = 2(x + 2)

Reorder the terms:
-2[x + -3(-1 + x) + -5] = 2(x + 2)
-2[x + (-1 * -3 + x * -3) + -5] = 2(x + 2)
-2[x + (3 + -3x) + -5] = 2(x + 2)

Reorder the terms:
-2[3 + -5 + x + -3x] = 2(x + 2)

Combine like terms: 3 + -5 = -2
-2[-2 + x + -3x] = 2(x + 2)

Combine like terms: x + -3x = -2x
-2[-2 + -2x] = 2(x + 2)
[-2 * -2 + -2x * -2] = 2(x + 2)
[4 + 4x] = 2(x + 2)

Reorder the terms:
4 + 4x = 2(2 + x)
4 + 4x = (2 * 2 + x * 2)
4 + 4x = (4 + 2x)

Add '-4' to each side of the equation.
4 + -4 + 4x = 4 + -4 + 2x

Combine like terms: 4 + -4 = 0
0 + 4x = 4 + -4 + 2x
4x = 4 + -4 + 2x

Combine like terms: 4 + -4 = 0
4x = 0 + 2x
4x = 2x

Solving
4x = 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
4x + -2x = 2x + -2x

Combine like terms: 4x + -2x = 2x
2x = 2x + -2x

Combine like terms: 2x + -2x = 0
2x = 0

Divide each side by '2'.
x = 0

Simplifying
x = 0

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